-15t^2+600t+50=0

Solution for -15t^2+600t+50=0 equation:

-15t^2+600t+50=0

a = -15; b = 600; c = +50;
Δ = b2-4ac
Δ = 6002-4·(-15)·50
Δ = 363000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{363000}=\sqrt{12100*30}=\sqrt{12100}*\sqrt{30}=110\sqrt{30}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-110\sqrt{30}}{2*-15}=\frac{-600-110\sqrt{30}}{-30}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+110\sqrt{30}}{2*-15}=\frac{-600+110\sqrt{30}}{-30}
$